Page 292 - Area 9 - Relevant Document

39

= 1123.98- 257.76 = 280.99 – 257.76 = 23.24

4

ESS = TSS – tSS

= 27.03 – 23.24 = 3.79

STEP 4.Compute the MS (Mean Squares) for the different SVs (sources of
variation)

tMS=tSS= 23.24 = 5.83

tdf 4

EMS = ESS = 3.79 = 0.25

Edf 15

STEP 5. Determine the computed F value and make statistical conclusions
by comparing it with the tabular F value.

Fc = tMS = 5.81 = 23.24

EMS 0.25

As could be found in the points for the distribution of F using tdf of 4 andEdf
of 15, the tabular F value is 3.06 and 469 for 5% and 1% level of significance
respectively.
The result therefore is highly significant ( **) which means that the
application of varying rates of Nitrogen significantly affected the yield of rice
and further indicates that one or more pairs of treatment means are different
from each other.

STEP 6. Construct the ANOVA table and fill all the computed values as
shown in the ANOVA table below.

F- VALUE