2 2
= √ (12√2) + (6√2)
= √288 + 72
= √216
= 6√6 cm
3.
H G
P
E F O
O P
D C A C
A
A B = ×
= √ + 6×12√2
2
2
=
18
2
2
= √ (12√2) + 6
= 4√2 satuan
= √288 + 36
= √324
= 18
4.
H G
P’
E F
G’ D C
P A
A B
= √ +
2
2
2
2
= √ (3√2) + 6
= √18 + 36
Jarak Dalam Ruang __ Matematika Wajib XII ____ 16