= √54
= 3√6
′
′
= ×
′
= 6×6√2
3√6
′
= 4√3 cm
5.
T
A’
C
A
D
B
= √ −
2
2
2
5
= √ 5 − ( √2)
2
2
50 ×
′
= √25 − =
4
5
5× √2
′
50
= √ = 5 2
4 √6
2
5
′
5
= √2 = √3 cm
2 3
= √ +
2
2
2
5
2
= √ ( √2) + 5
2
50
= √ + 25
4
150
= √
4
5
= √6
2
Jarak Dalam Ruang __ Matematika Wajib XII ____ 17