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or,            − I  R  − (I  − I ) R  − E  = 0               (iii)
                                               1
                                                   3
                                                          2
                               2
                                         2
                                   2
               In the two equations, i.e., in (ii) and (iii), if the values of R , R , R , E , and
                                                                                      1
                                                                                          2
                                                                                                   1
                                                                                               3
               E , are known, we can calculate the branch currents by solving these
                 2
               equations.
                  Students need to note that Kirchhoff’s laws are applicable to both dc and
               ac circuits.
                  Let us apply KVL in a circuit consisting of a resistance, an inductance, and
               a capacitance connected across a voltage source as has been shown in Fig.

               2.21. We will equate the voltage rise with the voltage drops.
















                                                Figure 2.21 Application of KVL

                  The voltage equation is








                  While solving network problems using Kirchhoff’s laws we frame a
               number of simultaneous equations. These equations are solved to determine

               the currents in various branches in a circuit. We will discuss solving of
               simultaneous equations by the method of determinants or Cramer’s Rule.




                        2.5.3 Solution of Simultaneous Equations Using Cramer’s Rule

               Let the three simultaneous equations written for a network problem be of the
               form


                                                  a x + b y + c z = d    1
                                                   1
                                                                  1
                                                           1
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