Page 134 - Basic Electrical Engineering

To find I , we assume potential at point k as V . We can write, V + 3 = V B
K
K
3
and

Applying KCL at node B,

I = I + I 3
1
2

or,

or, 17 V − 6 V = 98 (i)
B
C

Applying KCL at node C,

I = I + I 5
3
4

or,

or, 21 V − 34 V = 27 (ii)
C
B

Solving eqs. (i) and (ii), we get

V = 7.01 V; V = 3.537 V
C
B
and current in 8 Ω resistor,