Page 143 - Basic Electrical Engineering
P. 143

Figure 2.38


               The circuit diagram of two batteries supplying a common load has been
               shown in Fig. 2.38.


               Apply KVL to mesh ABEFA and BCDEB after arbitrarily showing the

               branch current directions. Current through the batteries are I  and I  and
                                                                                        1
                                                                                                2
               through the load is I  + I , respectively, as has been shown.
                                        1
                                             2
                  From mesh ABEFA,


                            40 − 2I  + 4 (I ) − 44 = 0
                                          2
                                  1
                                − 2I  + 4I  = − 40 + 44
                                        2
                                 1
                        2I  − 4I  = 40 − 44 or, 2I  − 4I  = −4                                 (i)
                                                           2
                                                    1
                               2
                        1
               From mesh BCDEB


                                        − 6(I  + I ) + 44 − 4I  = 0
                                             2
                                                           2
                                        1
                        − 6I  − 10I  = − 44 or, 6I  + 10I  = 44                                (ii)
                                   2
                                                            2
                                                    1
                           1
               Students are once again reminded that while going through the loop or the
               mesh, the following sign connection has been followed.


                   1.  Moving from negative terminal towards positive terminal of a battery is considered positive
                     voltage, i.e., as voltage rise
                   2.  Voltage drop in the resistor is taken as negative when moving in the direction of current flow.
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