Page 146 - Basic Electrical Engineering
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− 3I + 2I = − 2 (iii)
1
3
= −1[6 − 0] − 2[−4 + 27] − 4[0+ 9]
= −88
Similarly,
Similarly
Current through galvanomeneter
Example 2.16 Applying KCL, determine current I in the electric circuit to
S
make V = 16 V in the network shown in Fig. 2.40.
0
