Page 150 - Basic Electrical Engineering
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17V − 6V = 98 (i)
B
C
Applying KCl at node C we get
21V − 34V = 27 (ii)
B
C
Solving eq. (i) and (ii), we get,
Voltage of node B, V = 7.0133 V
B
Voltage of node C, V = 3.5376 V
C
Current in 8 Ω Resistor
Example 2.19 Two batteries of EMF 2.05 V and 2.15 V having internal
resistances of 0.05 Ω and 0.04 Ω, respectively are connected togather in
parallel to supply a load resistance of 1 Ω. Calculate using the superposition
theorem, current supplied by each battery and also the load current
Figure 2.43
Solution:
