Page 163 - Basic Electrical Engineering
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Figure 2.63
Solution:
Step 1:– Remove load resistance through which current is required to be
calculated.
Figure 2.64
Applying KVL in the loop CDEFC,
15 − 3I − 6I − 6 = 0
or, 9I = 9
or, I = 1
voltage across CD
= 15 − 3I
= 15 − 3 × 1
= 12 V
