Page 209 - Basic Electrical Engineering
P. 209
Multiplying eq. (6) by eq. (7),
Now, adding eqs. (8), (9), and (10)
or,
Earlier we calculated
[as in eq. (7)]
Therfore, R R + R R + R R = R R
2 3
1 2
12 3
3 1
Dividing both sides by
Similarly R and R can be calculated.
23
31
Thus, from eqs. (5), (6), and (7), R , R , and R in terms of R , R , and R 3
2
1
31
12
23
across terminals A, B, and C are calculated.