Page 398 - Basic Electrical Engineering
P. 398
At resonance, impedance of the circuit is equal to R. Therefore, the maximum
current that will flow is equal to
To calculate the voltage drop across the circuit components, we calculate X L
and X at the resonance frequency first.
C
−3
X = 2πf L = 2 × 3.14 × 356 × 20 × 10 Ω
0
L
= 44.7 Ω
voltage drop across L, V = I X = 5 × 44.7 = 223.5V
0 L
L
voltage drop across R, V = I R = 5 × 10 = 50V
0
R
Note that the voltage drop across R is the same as the supply voltage, i.e., 50
V. Voltage drop across the capacitor should be the same as the voltage drop
across inductive reactance X . Let us calculate V .
L
C
Substituting values
Thus, V = V = 223.5 V
L
C
Q-factor

