Page 506 - Basic Electrical Engineering
P. 506

Figure 5.24


                  This is an example of a parallel circuit. As current in an electric circuit gets
               divided into two parallel branches, the flux produced in the central limb will

               get divided into the two outer limbs.
                  We will calculate the MMF required for the central limb as also for any of
               the outer limbs which will maintain the desired flux in the core. For a flux

                                        2
               density of 1.2 Wb/m , the value of H has been given. Let us calculate the flux
               density in the central limb first.


               Flux density in the central limb,




                  The Flux density in the outer limb will be the same as that in the central
               limb since half the flux is available in each of the outer limbs and their cross-
               sectional area is half of that of the central limb.








                                                                                            2
                  The corresponding H i.e., AT/m for flux density of 1.2 Wb/m  has been
               given as 750.

                  The total MMF required = MMF required for the central limb + MMF
               required for one outer limb (and not for both the limbs).
               Since








               Total MMF required
   501   502   503   504   505   506   507   508   509   510   511