Page 575 - Basic Electrical Engineering

1100 = 4.44ϕ ×50×500
m

or,

−3
ϕ = 9.9 ×10 Wb
m

Example 6.5 The maximum flux density in the core of a 1100/220 V, 50 Hz,
2
100 kVA transformer is 3.5 Wb/m . Calculate the area of cross section of the
core and the number of turns of the primary and secondary windings if the

EMF per turn is 5.5 V.

Solution:

V = E = 1100 V
1
1
EMF per turn × No. of turns = total induced EMF

or,
5.5 × N = E 1
1

or,

Again,

E = 4.44 ϕ f N 1
m
1
or,