Page 571 - Basic Electrical Engineering
P. 571
Solution:
Let E and E be the EMFs induced in primary and secondary windings,
1
2
respectively. Here, N = 1000 and N = 500.
1
2
E = 4.44 ϕ f N 1
1
m
−3
= 4.44 × 2 × 10 ×50× 1000.
= 444 V
and
E = 4.44ϕ f N 2
2
m
−3
= 4.44 ×2×10 ×50×500
= 222 V
We obsere that,
and
Therefore
Example 6.2 A transformer has 900 turns on its primary winding and 300
turns on its secondary. A voltage of 230 V at 50 Hz is connected across its
2
primary winding. The cross-sectional area of the core is 64 cm . Calculate the
magnitude of the induced EMF in the secondary winding. Also calculate the
value of maximum flux density in the core.
Solution:
