Page 105 - Fiber Optic Communications Fund
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86                                                                Fiber Optic Communications



            The net accumulated dispersion is
                                                      L
                                        |D L    + D DCF DCF | ≤ 1100 ps/nm.                  (2.259)
                                          TF TF
            Therefore, the accumulated dispersion of the DCF should be

                                                 L
                                             D DCF DCF  < −3380 ps/nm.                       (2.260)




            Example 2.18
            Let the input field envelope be
                                                      [          ]
                                                         2
                                                         t (1 + iC)
                                            s (t)= A exp −         ,                         (2.261)
                                            i
                                                           2T 2
                                                              0
            where C is the chirp parameter. Show that the field envelope at the fiber output is
                                                       [           ]
                                                AT 0      (1 + iC) t 2
                                          s (t)=    exp −           ,
                                           o                   2
                                                 T
                                                  1          2T
                                                               1
            where
                                               [(  2      )     ] 1∕2
                                           T =   T +  LC − i L  .
                                                              2
                                                      2
                                            1
                                                  0
            Plot the power and frequency deviation  at different fiber lengths for  C > 0 and  C < 0. Ignore fiber
                                                                                  2
                                                                        2
            loss and  .
                    1
            Solution:
            Using Eqs. (2.150) and (2.152), we find
                                                   A            2
                                             ̃ s (f)=  exp [−(f∕a) ],                      (2.262)
                                              i
                                                   a
            where
                                                   2
                                                  a =  1 + iC .                              (2.263)
                                                       2T 2
                                                           0
                                                              2
                                                                          2
                                                         2
            The output field envelope is given by Eq. (2.155), with b = a ∕(1 − i2 La ) as,
                                                                       2
                                                       [           ]
                                                AT 0      (1 + iC) t 2
                                          s (t)=    exp −           ,                        (2.264)
                                           o
                                                 T 1         2T 2
                                                               1
            where
                                                  2              1∕2
                                           T =[(T +  LC)− i L]  .                        (2.265)
                                            1     0   2       2
            As in Example 2.6, the output pulse width can be calculated as
                                                                         1∕2
                                                  (         ) 2  (   ) 2
                                                 ⎡     C L       L  ⎤
                                   T out  = T in  ⎢  1 +  2    +   2    ⎥  .                 (2.266)
                                    FWHM     FWHM         2         2
                                                 ⎢      T          T    ⎥
                                                 ⎣       0          0   ⎦
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