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352                                                               Fiber Optic Communications


                         s(t)cos(ω IF t + ∆φ)               t = T b
                                                                        Decision
                                               H s  (ω)
                                                                        device
                                                          r(T b ) = u(T b ) + n F (T b )
                                 cos(ω IF t + ∆φ)


                            Figure 8.14  Matched filter for the baseband signal after down-conversion.

            Alternatively, the photocurrent can be down-converted to the baseband by demodulating synchronously and
            the result is applied to a filter H (), matched to the baseband signal s(t), as shown in Fig. 8.14. In this case,
                                      s
            we find that (see Example 8.7)
                                                         4E 1
                                                    =     .                                (8.129)
                                                   max    het
                                                         N
                                                          0
            In both cases, we obtain the same   and, using Eq. (8.129) in Eq. (8.39), we obtain
                                         max
                                                        (√     )
                                                   1         het
                                              P =    erfc                                    (8.130)
                                               b
                                                   2         2
            where
                                                         E av
                                                    het  =  .                              (8.131)
                                                        N het
                                                          0
            8.4.1.1  ASE Limited Systems
                                   2
            When  ASE  ≫ shot ∕(4A 2 LO R ), the second term of Eq. (8.122) can be ignored. In this case,
                                                         ASE
                                                    het
                                                  N   =     .                                (8.132)
                                                    0     2
            Now, Eq. (8.130) reduces to
                                                        (√      )
                                                   1        E av
                                              het
                                             P  =   erfc          .                          (8.133)
                                              b    2        
                                                             ASE
            Under the same conditions, from Eq. (8.85), we have
                                                  N homo  =                                (8.134)
                                                   0      ASE
            and
                                                        (√      )
                                            P homo  =  1  erfc  E av  .                      (8.135)
                                             b     2        
                                                             ASE
            Thus, the performances of the homodyne and heterodyne receivers are the same for a PSK signal when the
            ASE is dominant.

            8.4.1.2  Shot Noise-Limited Systems
                                     2
            In this case,   ≫  A 2  R and we ignore the first term of Eq. (8.122) and use Eq. (8.82) to obtain
                       shot   ASE LO
                                                      shot,eff  hf
                                               N het  =     =                                (8.136)
                                                0      2 2
                                                     2R A     2
                                                         LO
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