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Performance Analysis                                                               371


           Combining Eqs. (8.267) and (8.273), we obtain

                         1
                     P = [P(1|0)+ P(0|1)]
                      b
                         2
                                                                   √
                           ⎧                                                         ⎫
                                [   DD  (      )]           ⎛            (        ) ⎞
                         1 ⎪               2                √  DD    DD      2     ⎪
                       =     exp −      1 +       + 1 − Q 1  ⎜ 2   ,    1 +    ⎟  .    (8.274)
                         2  ⎨       2        DD           ⎜                   DD ⎟  ⎬
                           ⎪                                                         ⎪
                                                            ⎝                      ⎠
                           ⎩                                                         ⎭
           Note that Eq. (8.274) is the same as Eq. (8.230) obtained for the case of a heterodyne receiver if we replace
            het  by 2 DD . In this analysis, we have ignored the receiver noise mechanisms such as shot noise and thermal
           noise and assumed that the optical filter is a matched filter. Without these approximations and assumptions,
           the analysis is quite cumbersome. When the optical filter is not matched to the transmitted signal, analyti-
           cal expressions can be obtained using the approaches in Refs. [7]–[9]. In a simplified approach, chi-square
           distributions are approximated by Gaussian distributions and the BER can be estimated by calculating the
           Q-factor as in Chapter 7. This Gaussian approximation gives reasonably accurate results for OOK, although
           it is found to be inaccurate for DPSK signals with direct detection [7].


           8.5.2  FSK

           For FSK with direct detection, the transmitted signals s (t) and s (t) are the same as those in Section 8.4.3.
                                                               0
                                                       1
           (Eq. (8.166)). Since the energies of signals s (t) and s (t) are equal, we use the matched filters shown in
                                               1
                                                       0
           Fig. 8.21 (similar to Fig. 8.7). The matched filters can be realized as a bank of band-pass filters. As before,
           the matched filters need not be synchronized with the received signal, but can differ by a phase factor .The
           signal field u (t) and noise field n (t) at the output of the matched filters are given by
                     j
                                     F j
                                               ∞
                                           1              −it
                                    u (t)=       ̃ x()H ()e  d, j = 0, 1,            (8.275)
                                     j    2 ∫ −∞    j
                                               ∞
                                           1               −it
                                   n (t)=        ̃ n ()H ()e  d, j = 0, 1.           (8.276)
                                    Fj    2 ∫ −∞  c  j

                                           u 1 (t) + n F1 (t)
                                                         t = T b
                                                  PD1
                                       H 1 (ω)      2
                    x(t) =                        |∙|        I (T b )
                                                             1
                    s(t)e *iω c t                                                 If I 1 (T b ) > I 0 (T b )
                Tx          ∑                                         Comparator  select ‘1’,
                         +
                                                                                  otherwise,
                           +                             t = T b                  select ‘0’.
                                       H 0 (ω)    PD0
                          n (t)e *iω c t          |∙| 2      I 0 (T b )
                          c
                                           u (t) + n F0 (t)
                                            0
                                    Figure 8.21  Direct detection receiver for FSK.
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