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Nonlinear Effects in Fibers                                                        421


           We expect that the displacement x(t) should also change harmonically in the steady state and try a trial solution

                                              x(t)= B exp (−it).                          (10.7)
           Substituting Eqs. (10.7) and (10.6) into Eq. (10.5), we obtain

                                                      E q
                                                       0 e
                                               B =    2                                     (10.8)
                                                           2
                                                   m( −  )
                                                      0
           and
                                                      q e
                                             x(t)=    2     E .                             (10.9)
                                                             x
                                                          2
                                                  m( −  )
                                                      0
           The dipole moment of an atom is defined as
                                                        q 2 e
                                           p = q x =    2     E .                          (10.10)
                                                e
                                                               x
                                            x
                                                            2
                                                    m( −  )
                                                        0
           In general,
                                                      q 2 e
                                              p =          E.                              (10.11)
                                                     2
                                                          2
                                                  m( −  )
                                                     0
            Our next step is to determine the electromagnetic field generated by the oscillating electron charge cloud.
           Each atom acts as a current source since the oscillating electron cloud can be imagined as a tiny current
           element. One of Maxwell’s equations in the presence of a current source is (Eq. (1.47))
                                                           E
                                              ∇× H = J +   .                             (10.12)
                                                         0
                                                           t
           Consider an incremental volume dV = Adx of an atomic system as shown in Fig. 10.2. Using Eq. (10.10), the
           current I is given by
                                             dq   dq dx   1 dq dp x
                                          I =   =      =         .                         (10.13)
                                             dt   dx dt  q dx dt
                                                          e
           Let N be the number of atoms per unit volume. The charge in volume dV is
                                            dq = q NdV = q NAdx                            (10.14)
                                                 e        e
           or
                                                 dq
                                                    = q NA.                                (10.15)
                                                       e
                                                 dx
           Using Eq. (10.15) in Eq. (10.13), we obtain
                                                       dp x
                                                 I = NA   .                                (10.16)
                                                        dt
           Since J = I∕A, we obtain
                x
                                                       dp x
                                                 J = N    .                                (10.17)
                                                  x
                                                       dt
           In general,
                                                       dp
                                                  J = N  .                                 (10.18)
                                                       dt
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