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Nonlinear Effects in Fibers                                                        447








                               XPM phase shift









                                                     L − Z 0

                                       Z 0
                                                                            Z
                                         dZ
                                                        L

                          Figure 10.14  Conversion of XPM-induced phase shift into amplitude shift.


           where

                                                       2
                                                 x =   ∕2,                            (10.201)
                                                     2
                                                     1 − exp (−ax)
                                           L EFF (a, x)=        .                         (10.202)
                                                          a
           Since the power modulation of the pump fluctuates as the bit pattern changes, the distortion of the signal due
                    ̃
           to XPM, ΔA (), changes as a function of the bit pattern. To quantify the magnitude of the XPM distortion,
                     s
           let us calculate the PSD of the XPM distortion as
                                           ̃ (T)  2         (T)   2
                                                            p
                                            s
                                        ⟨|ΔA ()| ⟩      ⟨|P ()| ⟩
                            () = lim            = lim
                           XPM
                                    T→∞      T        T→∞     T
                             2    ixL                     −ixL                   2
                          ×  P |e L  [( − id + ix), L]− e  L  [( − id − ix), L]| ,  (10.203)
                               s0    EFF       p              EFF       p
           where T is the time interval of the bit pattern and
                                                     T∕2
                                            (T)
                                           ̃
                                                              it
                                         ΔA ()=  ∫    ΔA (t)e dt.                       (10.204)
                                                           s
                                            s
                                                    −T∕2
            As an example, consider an OOK system that uses unipolar NRZ pulses. The pump field envelope may be
           written as
                                                           (       )
                                            √
                                                   ∑         t − nT b
                                      q (t)=  P       a rect         ,                    (10.205)
                                       p       p0      n       T
                                                    n           b
           where a is a random variable which takes the values 0 or 1 with equal probability,
                 n
                                                             (       )
                                                     ∑   2     t − nT b
                                               2
                                   P (t)= |q (t)| = P   a rect         .                  (10.206)
                                     p     p       p0    n       T
                                                      n           b
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