Page 491 - Fiber Optic Communications Fund
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472                                                               Fiber Optic Communications


            by J complex coefficients (or 2J real coefficients) of the expansion in a set of orthonormal basis functions.
            Let us represent the signal and noise fields using an orthonormal set of basis functions as
                                                       J−1
                                                       ∑
                                               s (T)=    s F (T),                           (10.352)
                                                          j j
                                                in
                                                       j=0
                                                      J−1
                                                      ∑
                                                n(T)=    n F (T),                           (10.353)
                                                          j j
                                                      j=0
            where {F (T)} is a set of orthonormal functions,
                    j
                                            ∞
                                                   ∗
                                              F (T)F (T)dT = 1if j = k
                                          ∫    j   k
                                           −∞
                                                         = 0 otherwise.                     (10.354)
            Because of the orthogonality of the basis functions, it follows that
                                                    ∞
                                                           ∗
                                              n =  ∫  n(T)F (T)dT.                          (10.355)
                                               j
                                                           j
                                                   −∞
            Using Eqs. (10.355) and (10.348)–(10.350), we obtain
                                                   < n >= 0,                                (10.356)
                                                      j
                                                  ∗
                                              < n n > =  if j = k
                                                 j k
                                                     = 0 otherwise,                         (10.357)

                                                  < n n ) >= 0.                             (10.358)
                                                     j k
            Using Eqs. (10.352) and (10.353) in Eq. (10.347), we find
                                                     J−1
                                                     ∑
                                             s (T)=    (s + n )F (T).                       (10.359)
                                              out        j  j  j
                                                     j=0
            Suppose ‘1’ is transmitted (a = 1). We choose F (T)= p(T) so that
                                                   0
                                   0
                                                    √
                                                 s =  E if j = 0
                                                 j
                                                  = 0 otherwise.                            (10.360)
            Eq. (10.359) can be written as

                                                              J−1
                                                √             ∑
                                        s (T)=( E + n )p(T)+     n F (T).                   (10.361)
                                         out           0          j j
                                                              j=1
            Let us assume that the signal power is much larger than the noise power and s (T) is real. Let
                                                                          in
                                               n(T)= n (T)+ in (T),                         (10.362)
                                                      r      i
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