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Analogy                                                                                             153

                                                   Concept Deviator


                                    3
            1.   (d)  relationship, a : (a  + a)                          in  option (c), the  same follows i.e. difference
                                                                                   rd
                                 2
            2.   (c)  relationship, (a  + 1) : a                          between 3 and 2 nd  Number is 3, which is first
                                 3
                                          3
            3.   (d)  relationship, a  : (a + 1)  + 1                     number.
                               3
            4.   (c)  pattern is (a  + a)                        12.  (b): The pattern is (3, 3 × 6 = 18, 18 × 2 = 36)
                                                                          then,
            5.   (b)  relationship is a: (a + 89)
                                                                         (4, 4 × 6 = 24, 24 × 2 = 48) which is option (b).
            6.   (b)  relationship is a: (7/2 a)
            7.   (d)  relationship is a: a(a + 1)                13.  (d)  The   pattern  is   (6   9   15,   13   28)
                                              2
            8.   (d)  it is in the form, 210 = (15)  – 15 and 380 =       then, option (d) follows the same pattern
                                                2
                            2
                    (15 + 5)  – (15 + 5), 182 = 13  + 13 and 342          i.e. (60    69,    82)
                    = 182 + 18                                                  9       13   2
                                                  2
                                   2
            9.   (c)  relationship is, (a  – 1 ) : [(a + 4)  + 1]  14.  (b)  The pattern is (6, (6)  =36, Reverse of 2nd 's
                                                                                                              2
                                                                          digits = 63) and option (b) has (8, (8)  =64,
            10.  (b)  100 = 5 × 20, 64 = 4 × 16, 80 = 4 × 20 and          Reverse is 46).
                    required number will be 3 × 16 is 48         15.  (d)  (23, 29, 37) all are prime numbers, Here option
            11.  (c)  2 is the first number and difference between 3 rd   (d) has all prime numbers.
                    and 2 nd  number is equal to first number. Hence,
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