Page 183 - Services Selection Board (SSB) Interviews

Inequality 179

Answer with Solution

Concept Applicator

1. (c) N = P ≤ F ≥ L = K Solution for 11 to 15
Hence F ≥ K. Which means either 1. (b) A ≥ B = C < D ≤ E
I (F = K) or II (F > K) follows I. D > A is not true, II. E > C is true.
2. (a) Z > T < M < J 2. (e) Split them as L > U ...(i)
Which means T < J. Hence I follows. Combining (i) and (ii),
But Z and J can’t be compared. Hence II does not We get L > U > Z or L > Z
follow. Hence I follows.
3. (e) C ≥ G ≥ Q = Z ≥ R Combining (ii) and (iv) we get K ≤ U < R or K < R
Hence G ≥ Z and I follows. Hence II follows.
Also C ≥ R and II follows. 13. (a) Y < J = P ≥ R > I
4. (d) A > B < C < D > E > F I. J > I is true, II. Y < R is not true.
E and C can’t be compared. Hence II does not follow. 14. (d) V ≥ K > M = N > S
Z and J can’t be compared. Hence I does not follow. K > T
Consequently II does not follow either.
I. T < N is not true, II. V = S is true.
5. (e) L > K > M ≥ N > O 15. (a) Split them as F ≤ X ...(i) X < A ...(ii)
Hence O < M and I follows.
R < X ...(ii) and X ≤ E ...(iv)
Also O < K and II follows. Combining (i) and (iv) we get
6. (b)
7. (d) F ≤ X ≤ F or F ≤ E.
8. (e) Hence I follow.
9. (a) From (i) and (iii) R and F can’t be compared. Hence
II does not follow.
10. (c)

Concept Builder

Solution for 1 to 7 4. (d) W ≤ D ...(i) D ≥ B ...(ii) B > H ...(iii)
1. (c) M < J ...(i) J ≤ R ...(ii) R = K ...(iii H and D can’t be compared from (ii) and (iii)
From (ii) and (iii) J≤ K or K ≥ J, ...(iv) Hence I does not follows
Hence either I (K = J) or II (K > J) follow Nor can W and B he be compared From (i) and (ii).
2. (e) N ≥ T ...(i) T = H ...(ii) N < W ...(iii) Hence II does not follows
Combining these we get W > N ≥ T = H 5. (b) F = T ...(i) T ≥ M ...(ii) M ≤ R ...(iii)
Hence W > T and I follows. From (i) and (ii) F ≥ M ...(iv)
Also H ≤ N and II follows
3. (a) F < R ...(i) R ≤ V ...(ii) V ≥ T ...(iii) Hence M ≤ F and II follows
From (i) and (ii) F < V... (iv) But R and F can’t be compared From (iii) and (iv)
Hence F > V and I follows Hence I does not follow
But F and T can’t be compared From (iii) and (iv) 6. (a) H ≥ N ...(i) N > R ...(ii) R < J ...(iii)
Hence II does not follow