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Inequality                                                                                          181

                                                    Concept Cracker


            Solution for 1 to 6        [Canara Bank (PO) 2009]        From (ii) and (iii) K and W can’t be compared.
            1.   (a) H ≤ T ...(i) T < L ...(ii) L = F ...(iii)        Hence I does not follow.
                Combining these we get H ≤ T < L = F.                 From (i) and (ii) H and M can’t be compared.
                Hence F > H and I follows.                            Hence II does not follow.
                But H < L and Hence II (H ≤ L ) does not follow.  11.  (d) F ≥ K ...(i) K > B ...(ii) B ≤ M ...(iii)
            2.   (c) V > I ...(i) I ≥ M ...(ii) M ≤ Q ...(iii)        From (i) and (ii) F can’t be compared with B and
                From (ii) and (iii) I and Q, can’t be compared. But   consequently with M. Hence neither II nor I follows.
                I and II make a complementary pair. Hence either I    12.  (e) R ≥ T ...(i) T = M ...(ii) M > D ...(iii)
                (I ≤ Q) or II (I ≥ Q) follows.                        Combining these we get R ≥ T = M > D.
            3.  (b) P < W ...(i) W ≥ D ...(ii) D > J ...(iii)         Hence D > T and I follows.
                From (ii) and (iii) W ≥ D > J or J < W ...(iv)        Also R ≥ T and II follows
                Hence II follows. However, From (i) and (iv) we can    Solution for 13 to 18   [United Bank of India (PO)]
                conclude that J and P can’t be compared. Hence I   13.  (a) J > M ...(i) M < K ...(ii) K ≥ D ...(iii)
                does not follow.                                      From  (i)  and  (ii)  J and  K can’t be compared  and
            4..  (d) E < U ...(i) U = R ...(ii) R > F ...(iii)        consequently  J and D can’t be compared. Hence
                From (i) and (ii) E < R ...(iv)                       neither III nor I follows. From (ii) and (iii) D and M
                Now, From (iii) and (iv) E and F can’t be compared    can’t be compared
                Hence neither I nor II follows.                       Hence II does not follow.
            5.  (d) T ≤ J ...(i) J ≥ I ...(ii) I < W ...(iii)    14.  (c) R = K ...(i) K ≤ F ...(ii) F < K ...(iii)
                From (ii) and (iii) J and W can’t be compared. Hence      Combining these we get R = K ≤ F < N.
                I does not follow                                     Hence K > R and I follow.
                From (i) and (ii) T and I can’t be compared. Hence II      Also F ≥ R. Hence either II (F = R ) or III (F = R)and
                does not follow.                                      follows.
            6.  (a) K ≥ D ...(i) D > L ...(ii) L < J ...(iii)    15.  (b) R ≤ D ...(i) D = N ...(ii) N > F ...(iii)
                From (i) and (ii) K ≥ D > L or K > L ...(iv)          From (ii) and (iii) D = N > F or F < D ...(iv)
                Hence I follows.                                      Hence I follow.
                However, From  (iii)  and (iv)  J and  H can’t be      From (i) and (iv) F and R can’t be compared.
                compared. Hence II does not follow.                   Hence II does not follow.
            Solution for 7 to 12     [Indian Overseas Bank (PO)]  16.  (e) H < T ...(i) T ≤ B ...(ii) B > R ...(iii)
            7.  (b) R ≤ N ...(i) N ≥ F ...(ii) F > B ...(iii)         From (i) and (ii) we get H < T ≤ B or B > H.
                From (i) and (ii) F and R can’t be compared. Hence      Hence II follow.
                I does not follow.
                Combining (ii) and (iii) we get N ≥ F > B or N > B      From (ii) and (iii) T and R can’t be compared.
                or B <  N. Hence II follows.                          Hence III does not follow.
            8.  (c) H = W ...(i) W ≤ R ...(ii) R > F ...(iii)    17.  (b) M ≥ D ...(i) D < K ...(ii) K ≤ N ...(iii)
                From (i) and (ii) H = W ≤ R or R ≥ H,                 From (i) and (ii) K and M can’t be compared. Hence
                                                                      I  does not follow.
                Hence either I  (R=H) or II (R > H) follows.          From (ii) and (iii) D < K ≤ N or N > D.
            9.  (a) M < T ...(i) T > K ...(ii) K = D ...(iii)         Hence II follows. From (i) and II, M and N can’t be
                From (ii) and (iii) T > K = D or D < T.               compared. Hence III does not follow.
                Hence I follow                                   18.  (d) F ≤ B ...(i) B = H ...(ii) H ≥ K ...(iii)
                From (i) and (ii) K and M can’t be compared.          From (i) B F. Hence I follows.
                Hence II does not follow.                             From (ii) and (iii) B = H ≥ K or B ≥ K or K ≤ B can’t
            10.  (d) H > W ...(i) W > M ...(ii) M ≥ K ...(iii)        be compared. Hence II does not follow.
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