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QB-48                                                                            Miscellaneous Question Bank
                           6km                                        LHS ⇒ 42 × 4 + 12 ÷ 20 – 9
                                                   N
                                                                      By applying the operations in sequence, from left to
                                                                      right,
                5km                  5km    W             E           168 + 12 ÷ 20 – 9

                                                                      180 ÷ 20 – 9
                                                   S
                   START                                              9 – 9 = 0 = R. H. S.
                Sunder is 6 km far from the starting point.      294. (c)  After changing ‘+’  and ‘–’,  8  and 7  the
            285. (a)                                                      appropriate equation is,
                            5km                                           6 + 8 × 2 – 7 = 0.
                                                                      L.H.S. = 6 – 7 × 2 + 8
                                                                                  6 – 14 + 8
                                        4km                                       14 – 14 = 0 = R. H. S.
                 5km                                             295. (a) or (d)
                                               Finish                 Given, X – Y – Z  ⇒  X   Y   Z
                                                                                           ≥
                                                                                                ≥
                                     START     1km
                                                                      Both options (a) and (d) indicate that X < Y, which
                                                                      goes against the given information.
                                 6km                                  So, either (a) or (d).
                Have to run in west direction to reach the point of   296. (b)  5 × 6 ÷ 5 + 8 = 14
                start.                                           297. (d)  40 + 12 ÷ 3 × 6 – 60
                     MATHEMATICAL OPERATION                           =   40 + 4 × 6 – 60
            286. (a)                                                  =   40 + 24 – 60
            287. (a)
            288. (b)                                                  =   64 – 60 = 4
            289. (c)  2 × 4 – 3 + 4.                             298. (c)  25 ÷ 3 × 7 – 8 + 12 = 19.3
                     8 – 3 + 4                                   299. (d)  4 × 3 × 4 = 48
                      = 9                                        300. (a)   a   b # c   d
            290. (b)  9 + 5 + 4 = 18 ÷ 9 + 16
                                                                      a > b < c = d.  i.e  b < d
                     = 18 = 18.                                    301. (a)  9 ÷ 4 × 2 + 5 ÷ 10 – 3
            291. (b)
                                                                                   5
                                                                          9
                After changing ‘+’ = ÷, ‘–’ = ×                       =  42  ×  2 + 10 2 − 3
                                      ‘×’ = ‘+’ ‘÷’ = –
                the equation,  46 – 6 + 4 × 5 ÷ 3 = 71                =  9  +  1  − 3
                CHS = 46 × 6 ÷ 4 + 5 – 3                                 2  2
                      = 276 ÷ 4 + 5 – 3                                  10
                                                                                  −
                     =69 + 5 – 3                                      =  2  −  3 = 5 3 =  2
                     = 74 – 3 = 71  R.H.S.                       302. (b)  162 – 52 ÷ 26 + 15 × 5
            292. (b)  18 + 6 – 4 × 2 ÷ 3 = 26                             = 162 – 2 + 75 = 235
                After chaning, the equation is,                                  NUMBER PUZZLE
                L.H.S., 18 × 6 ÷ 4 + 2 – 3                       303. (a)  2 × 3 × 5 × 4 = 120
                     108 ÷ 4 + 2 – 3                                  120 × 120 = 14400
                     27 + 2 – 3                                  304. (d)  The product of any two numbers in a sector is
                                                                          equal to the central number in previous sector.
                     29 – 3 = 26  R.H.S.                         305. (c)   First column, 10 + 12 + 4 + 10 =36 ÷ 2 = 18

            293. (c)  The given expression is 42 * 4 * 12 * 9 = 0     2  Column, 11 + 12 + 15 + 5 = 40 ÷ 2 = 20
                                                                       nd
                                                                       rd
                From option (c), 42, – 4 ÷ 12 × 20 + 9.               3  Column, 15 + 8 + 10 + 13 = 46 ÷ 2 =  23
                By coding, the equation becomes,                 306. (d)
                                                                 307. (b)
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