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QB-48 Miscellaneous Question Bank
6km LHS ⇒ 42 × 4 + 12 ÷ 20 – 9
N
By applying the operations in sequence, from left to
right,
5km 5km W E 168 + 12 ÷ 20 – 9
180 ÷ 20 – 9
S
START 9 – 9 = 0 = R. H. S.
Sunder is 6 km far from the starting point. 294. (c) After changing ‘+’ and ‘–’, 8 and 7 the
285. (a) appropriate equation is,
5km 6 + 8 × 2 – 7 = 0.
L.H.S. = 6 – 7 × 2 + 8
6 – 14 + 8
4km 14 – 14 = 0 = R. H. S.
5km 295. (a) or (d)
Finish Given, X – Y – Z ⇒ X Y Z
≥
≥
START 1km
Both options (a) and (d) indicate that X < Y, which
goes against the given information.
6km So, either (a) or (d).
Have to run in west direction to reach the point of 296. (b) 5 × 6 ÷ 5 + 8 = 14
start. 297. (d) 40 + 12 ÷ 3 × 6 – 60
MATHEMATICAL OPERATION = 40 + 4 × 6 – 60
286. (a) = 40 + 24 – 60
287. (a)
288. (b) = 64 – 60 = 4
289. (c) 2 × 4 – 3 + 4. 298. (c) 25 ÷ 3 × 7 – 8 + 12 = 19.3
8 – 3 + 4 299. (d) 4 × 3 × 4 = 48
= 9 300. (a) a b # c d
290. (b) 9 + 5 + 4 = 18 ÷ 9 + 16
a > b < c = d. i.e b < d
= 18 = 18. 301. (a) 9 ÷ 4 × 2 + 5 ÷ 10 – 3
291. (b)
5
9
After changing ‘+’ = ÷, ‘–’ = × = 42 × 2 + 10 2 − 3
‘×’ = ‘+’ ‘÷’ = –
the equation, 46 – 6 + 4 × 5 ÷ 3 = 71 = 9 + 1 − 3
CHS = 46 × 6 ÷ 4 + 5 – 3 2 2
= 276 ÷ 4 + 5 – 3 10
−
=69 + 5 – 3 = 2 − 3 = 5 3 = 2
= 74 – 3 = 71 R.H.S. 302. (b) 162 – 52 ÷ 26 + 15 × 5
292. (b) 18 + 6 – 4 × 2 ÷ 3 = 26 = 162 – 2 + 75 = 235
After chaning, the equation is, NUMBER PUZZLE
L.H.S., 18 × 6 ÷ 4 + 2 – 3 303. (a) 2 × 3 × 5 × 4 = 120
108 ÷ 4 + 2 – 3 120 × 120 = 14400
27 + 2 – 3 304. (d) The product of any two numbers in a sector is
equal to the central number in previous sector.
29 – 3 = 26 R.H.S. 305. (c) First column, 10 + 12 + 4 + 10 =36 ÷ 2 = 18
293. (c) The given expression is 42 * 4 * 12 * 9 = 0 2 Column, 11 + 12 + 15 + 5 = 40 ÷ 2 = 20
nd
rd
From option (c), 42, – 4 ÷ 12 × 20 + 9. 3 Column, 15 + 8 + 10 + 13 = 46 ÷ 2 = 23
By coding, the equation becomes, 306. (d)
307. (b)