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QB-50 Miscellaneous Question Bank
327. (b) 81 36 25
49 100 36 2
9 64 16 (4+2+7)–(3+1)=9
+ + + 4 9 7
139 200 77 3 1
328. (c) 4 × 6 × 9 = 694, 5 × 3 × 2 = 325 Similarly,
In the above problem, the left most number changes 9
its place and moves to right end side of the answer
figure. 6 ? 2 (9+6+2)–(4+3)
=17 –7=10
Hence, 7×8×2= 827 4 3
329. (a) In this perticular problem, the logic is– (4 + 2 + 7) – (3 + 1) = 9
2463 ⇒ (2 + 4 + 6) × 3 = 12 × 3 = 36 (9 + 6 + 2) – (4 + 3) = 17 – 7 = 10
5552 ⇒ (5 + 5 + 5) × 2 = 15 × 2 = 30 333. (a)
6732 ⇒ (6 + 7 + 3) × 2 = 16 × 2 = 32
330. (a) 5 6 7 8
−
−
−
−
7 5×( 7 5) 6×( 9 6) 7×( 107) 8 ×( 138)
= 10 = 18 = 21 = 40
6 ?
7 9 10 13
9 36
42 334. (c)
335. (a) 8 × 8 = 64, 12 × 12 = 144
11 × 11 = 121
6 × 6 = 36 336. (d) 3 4 5
7 × 6 = 42
9 × 6 = 54 2 3 4
1 2 3
25 5 2
331. (c) 14 29 ?
16 22 36 4 2 22 6 2
2
2
\ 3 + 2 + 1 = 14
2
2
2
49 7 2 4 + 3 + 2 = 29
2
2
2
5 + 4 + 3 = 50
337. (a)
64 8 2 338. (a)
9 16 1 3 2 16 1 2
x x 2
9 3 2 The difference increases by 1 from clockwise
4 15 1 2 2 15 1 2 direction.
339. (b) 4
81 9 2 26 6 3 26 7 5 ? 8
22 = 5 + 4 + 7 + 6 2 5 4
16 = 8 + 3 + 1 + x A B C
x = 4 340. (a) The logic is -
2
x = x = 16 3
15 = 3 + 2 + 9 + 1 5 12 4 → (5 × 3 × 4 × 2) ÷ 10 = 120 → 12
332. (b) The logic is 2 10