Page 275 - FUNDAMENTALS OF COMPUTER

NPP

NPP Number System, Boolean Algebra and Logic Circuits 275

Start

Take MSB of Dividend MSB

Subtract divisor

NO Need Yes
a
Borrow
?

Quotient bit is ‘1’

NO LSB Yes LSB
of
Dividend
Stop

Flow-Chart for Division (Restoring Method)
3.32 9’s Complement and 10’s 3.32 9’s H$m°påßb_|Q> VWm 10’s H$måßbr_|Q>
Complement
9’s complement : 9’s complement of a deci- 9’s H$m°påßb_|Q… {H$gr Xr JB© Xe_bd g§»`m Ho$
mal number is a number obtained after sub- àË`oH$ A§H$ _| go 9 H$mo KQ>mZo na Omo ZB© Xe_bd g§»`m
tracting each digit of the given number from 9. àmá hmoVr h¡, Cgo nhbr H$m 9’s H$m°påßb_|Q H$hVo h¢ Ÿ&
e.g. 235 is a decimal number. Subtract each O¡go 235 Ho$ àË`oH$ A§H$ _| go 9 KQ>mZo na 764 àmá
digit from 9. You will get 764. This is the 9’s hmoVm h¡Ÿ& AV… 764 H$mo 235 H$m 9’s H$m°påßb_|Q> H$h|Jo&
complement of 235.
10’s Complement: Incrementing the 9’s 10’s H$m°påßb_|Q … 9’s H$m°påßb_|Q> H$mo EH$ go ~‹T>mZo
complement by one gives 10’s complement. This na 10’s H$m°påßb_|Q àmá hmoVm h¡ Ÿ& Bgo {ZåZ gyÌ H$s
can be remembered as: ghm`Vm go `mX aIm Om gH$Vm h¡…
10’s complement = 9’s complement + 1 10’s H$m°påßb_|Q> = 9’s H$m°påßb_|Q> + 1
Thus, in order to get 10’s complement of a AWm©V² {H$gr g§»`m H$m 10’s H$m°påßb_|Q> àmá H$aZo
decimal number, first get the 9’s complement Ho$ {bE nhbo CgH$m 9’s H$m°påßb_|Q> {ZH$mbmo Am¡a EH$
and then add one to number. For example: Omo‹S>m|§& CXmhaUV…
10’s Complement of 42 is obtained as fol- Xe_bd g§»`m 42 H$m 10’s H$m°påßb_|Q> Bg Vah
lows : go {ZH$mbm OmEJm…