Page 30 - CHAPTER-1 (Electricity)

CHAPTER 1

ELECTRICITY

Therefore, the current flowing through each resistor is 0.4A.

∴ The potential difference across the first resistor,

V =IR =0.4×5=2V
1
1

The potential difference across the second resistor,

V =IR =0.4×10=4V
2
2
The potential difference across the third resistor,

V =IR =0.4×15=6V
3
3
Example 10:

Study the following electric circuit. Find the readings of:

(i) The ammeter

(ii) The voltmeter

Solution:
Fig 12:

In the given circuit, the resistance of 4Ω and bulb resistance of 2Ω are

connected in series, so equivalent resistance of the circuit,

R=R +R =4Ω+2Ω=6Ω
2
1
(i) The total current flowing in the circuit, ( )

Potential difference (V) 3
= = =0.5A
Total Resistance (R) 6

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