Page 34 - CHAPTER-1 (Electricity)

CHAPTER 1

ELECTRICITY

We get the following results for the current:

12
Current through 40Ω resistor, I = 40 =0.3A
1

Also, I =0.3A
2

12
Current through 20Ω resistor, I = 20 =0.6A
3

∴ Current, I=I +I +I =0.3A+0.3A+0.6A=1.2A
2
1
3

Checkpoint-5

1. A current of 2 ampere starts to flow in a A

2 3
system of conductors as shown. The
2A
potential drop (V -V ) will be D C
C
D
3 2
(a) +5 V (b)+8 V
B
(c)+10 V (d)-5 V
D
2. The effective resistance between the points 3 3

and in the figure 6
A C
(a)5 ohm (b)2 ohm
3 3
(c)3 ohm (d)4 ohm B

3. Four resistances are connected in a circuit as shown in the

figure. The electric current that flows through 4 ohm and 6 ohm

resistance is respectively 4 6

(a)2 amp and 4 amp
4 6
(b)1 amp and 2 amp

(c) 1 amp and 1 amp
20V
(d) 2 amp and 2 amp

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