Page 319 - Buku Paket Kelas 11 Matematika

Alternatif Penyelesaian:
2
a) ∫2x4 x3dx = ∫2x4.x3 dx
2
= 2∫x4.x3 dx
2
= 2∫x4+3 dx
 = 2 1 x11+1+c
11 2  +1 
2 
= 21x13+c 132 
 2
2
= 4x13+c.
b) ∫(x + 1)2 dx
13
= ∫x2 +2x+1dx
= 1 x2+1+ 2 x1+1+x+c 2+1 1+1
= 1x3+x2+x+c. 3
MATEMATIKA 311