Page 6 - TRIAL 2
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4.4    Principle of Conservation of Energy                 A
                                                                         P.E=100%           P.E=100%          C

                                                                         K.E = 0 % (v=0 %)   K.E=0 % (v=0%)

            1.  The  principle  of  conservation  of  energy  states
               that  energy  can  neither  be  created  nor
               destroyed, but can be converted from one form     h                  P.E= 0 %

               to another. This principle implies that the total                    K.E= 100%
               amount  of  energy  in  a  closed  system  remains                   (v=100%)
               constant.

                                                                                            B
                         Assume maximum energy is                 Example 1
                         100%, therefore, the total

                                P.E+K.E=100%  be
                         amount of energy, can                    A ball of mass 10g is placed at the top of a tower 50
                                                                  m  high  is  allowed  to  fall  freely.  Show  that  law  of
                         put in this simple formula
                                                                  conservation  of  energy  at  position  A,  B  and  C  is

                               P.E + K.E = 100%                   same.


                                                                                         A


            2.  A ball is roll down in U-curve, from position A to
               position  B,  and  then  to  position  c  and  finally   x = 10m
               back to position A.                                                 B
                                                                                          h = 50m
            3.  At position A:
                   Potential Energy (P.E) = 100 %                       40 m

                   Kinetic Energy (K.E) = 0 % (the ball stops for                   C             Ground
                   a moment)

            4.  From position A to B:
                   The potential energy of the ball gradually     Solution
                   decreases as it is changed to kinetic energy.
                                                                  Ball at position A, height from ground = 50 m
            5.  At position B:
                                                                  .  = ℎ
                   Potential Energy (P.E) = 0 % (the velocity of
                   the ball is 100 %)                             = 0.01 × 9.81 × 50
                                                                  = 4.905 
                   Kinetic Energy (K.E) = 100 %
                                                                         1   2
            6.  From position B to C:                             .  = 
                                                                         2
                                                                    1
                   The kinetic energy gradually changes back      = × 0.01 × 0
                                                                                2
                   to potential energy.                             2
                                                                  = 0  (Ball at rest)
            7.  At position C:
                                                                      = .  + . 
                   Potential energy = 100 %
                                                                  =4.905+0
                   Kinetic energy = 0 % (ball stops for a while)
                   Now the ball will oscillate from C to b and    =4.905 J
                   back to A. The oscillation cycle will repeat.
                                                                  Ball at position B, height from ground = 40 m

                                                                  P. E = mgh
                                                                  = 0.01 × 9.81 × 40


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