Page 69 - Modul Asam Basa
P. 69
Contoh Soal
-1
+
[H ] = 1 x 10 M
+
pH = - log [H ]
pH = - log 10 M
-1
pH = 1
2. Tentukan pH larutan sebelum dan sesudah diencerkan dari 200 mL
larutan Mg(OH)2 0,1 M ditambah 200 mL air!
Jawab:
-
2+
Reaksi ionisasi: Mg(OH)2 (aq) → Mg (aq) + 2OH (aq)
Sebelum dilakukan pengenceran
[OH ] = x. Mb
-
-
-1
[OH ] = 2 x 0,1 x 10 M
- -2
[OH ] = 2 x 10 M
pOH = - log [OH ]
-
-2
pOH = - log 2 x 10 M
pOH = 2 – log 2
pH = 14 – (2 – log 2) = 12 + log 2
Setelah dilakukan pengenceran
V₁ × M₁ = V₂ × M₂
200 mL x 0,1 M = 400 mL x M2
20 M = 400 x M2
M2 = 0,05 M
-
[OH ] = x. Mb
- -2
[OH ] = 2 x 5 x 10 M
[OH ] = 1 x 10 M
-1
-
+
pOH = - log [H ]
-1
pOH = - log 10 M
pOH = 1
pH = 14 – 1 = 13
E-MODUL KIMIA ASAM BASA 57