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Blast into Math!                                 Analatic nummer theora: ants, ghosts and giants



               Let’s follow these steps to prove that

                                                            1
                                                       lim    =0.
                                                       n→∞ n


                     1.  In this example, the n  term in the sequence is 1/n , so we can write the sequence as
                                           th
                                                                    1
                                                       ∞
                                                   {x n } n=1  ,  x n =  .
                                                                    n

                     2.  The role of L in the definition of the limit of the sequence is played by 0.
                     3.  A ghost number > 0 floats by…
                     4.  The ghost number needs to find a giant number N ∈ N  to squash all the “ants” up to the

                        N th   one, so that the ghost can then trap all the surviving ants between L −   and L +  .
                        Mathematically, the ghost needs to find a giant number N ∈ N  such that

                                                ∀n> N,      |x n − L| <.



                     5.  Since L =0 in this example, the ghost number > 0 is looking for a giant number so that

                                                    ∀n> N,     |x n − 0| <.


                        Now, let’s use the definition of x n =1/n . The ghost number needs to find N ∈ N  such that


                                                             1


                                                 ∀n> N,       − 0 <.

                                                             n

                        This is the same as
                                                               1
                                                    ∀n> N,       <.
                                                               n


                        With a bit of algebra, we see that this is the same as

                                                               1
                                                   ∀n> N,        <n.



                     6.  So, the giant number N  can be any natural number that is greater than 1/.
                     7.  We have just proven that, for any ghost number > 0, we can find a giant number N ∈ N
                        such that



                                                             1

                                                 ∀n> N,       − 0 <.

                                                             n




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