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Blast into Math!                                 Analatic nummer theora: ants, ghosts and giants



               The term with the highest power of  p  is


                                                         N!
                                                                  N
                                                     p N      = p .
                                                        N!0!

               Exercise: What is 0!? Please review #9 from Chapter 4 and #11 in Chapter 6.


               The next lowest power of  p  is


                                                        N!
                                             p N−1 m            = Nmp   N−1 .
                                                    (N − 1)!1!



               All the rest of the terms in the Binomial Formula are non-negative, so this means that

                                             N
                                                               N
                                                         N
                                            q =(p + m) ≥ p + Nmp         N−1 .
               Now, let’s look at (p/q) ,
                                    N

                                         N     N         N               N
                                        p       p         p               p
                                             =      =            ≤                 .
                                                                     N
                                        q       q N   (p + m) N     p + Nmp    N−1
               The additive identity can sneak into this equation disguised as


                                                             p N
                                                        1=      ,
                                                             p N



               and so

                                  p N         p N     1                 1             1
                                            =                =1 ∗              =            .
                                                N
                             N
                            p + Nmp    N−1    p 1+ Nm/p            1+ Nm/p        1+ Nm/p

               We are looking for a giant number N ∈ N  such that


                                                         p
                                                          N
                                                              <.
                                                         q

               Since


                                                    p            1
                                                     N
                                                         ≤             ,
                                                    q       1+ Nm/p





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