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Blast into Math!                                 Analatic nummer theora: ants, ghosts and giants



               We can keep doing this by defining

                                          x n =1 if the n th  elementof s n is 0,


                                          x n =0 if the n th  elementof s n is 1.


               Then, as it is defined, this sequence is not in S,  because it is different from s n forall n ∈ N. But, the set
                                              notin
               S  contains all sequences of 0 and 1, so we have a contradiction. Consequently, S  cannot be countable.



                                                            ♥

               Based on this proposition and geometric series, we can prove that there are uncountably many real
               numbers.


               Theorem 7.4.3 (Uncountably Many Real Numbers). The set of all real numbers is uncountable.

               Proof: For each sequence


                                                           ∞
                                                      {x n } n=1  ∈ S,

               since x n =0 or 1 for each n , for each N ∈ N , the partial sum


                                                    N                N
                                                       x n
                                                                       1
                                             S N =         ≤ T N =          .
                                                       10 n             10 n
                                                   n=1              n=1
               Since

                                                    1/10 − (1/10) N+1    1
                                              T N =                    < ,
                                                        1 − 1/10         9


                                                         1
                                                   T N < ,    ∀N ∈ N.
                                                         9


               Since S N ≤ T N ,

                                                         1
                                                   S N <     ∀N ∈ N.
                                                         9


               Each term


                                                           x n
                                                           10 n








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