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8.3 Using Pythagoras’ theorem



               )     Exercise 8.3


               1  Work out the length of the hypotenuse in each triangle.
                 The first two have been started for you.

                  a              a =      a  = b  + c 2            b                    a  = b  + c 2
                                                                                          2
                                            2
                                                 2
                                                                                              2
                                                 a = a =
                     b = 6 m     a =  b = 6 m 2  2    2         9 mm             9 mm 9 mm  2  2     2
                                         b = 6 m
                                                                9 mm
                     b = 6 m
                                                                                        a  = 9  + 12
                                          a  = 6  + 8
                                               c = 8 cm
                                                                           12 mm
                              c = 8 cm    a  = 36 + 64  12 mm           12 mm
                                                  c = 8 cm
                                            2
                                                        12 mm
                              c = 8 cm
                  c                                                d
                                     7 cm          5 m7 cm 7 cm     5 m 5 m
                                     7 cm
                                                   5 m
                             10 cm            10 cm 10 cm  9 m              9 m 9 m
                                                           9 m
                             10 cm
               2  Work out the lengths of the sides marked   in each triangle.
                 The first two have been started for you.

                  a             a = 5 cm         a  = b  + c 2     b        2.6 m             a  = b  + c 2
                                                      2
                                                                                                    2
                                                                                                2
                                                 2
                                                      a = 5 cm
                                                       2.6 m
                      b =                   b =   2   a = 5 cm  1 m          2.6 m    1 m        2    2     2
                                                       2
                                                           2
                               a = 5 cm     b =     5  = b  + 4                       1 m     2.6  = 1  + c
                                                      2.6 m
                     b =      c = 4 cm         25 = b  + 16    1 m
                                                    c = 4 cm
                                                       2
                                                    c = 4 cm
                                                  2
                             c = 4 cm           b  = 25 – 16
                                                  15 m
                  c         15 m                 13 cm      25 cm  d   13 cm     25 cm
                                                  15 m
                                                                                  25 cm
                           15 m                            25 cm      13 cm
                             9 m               13 cm 9 m
                                                   9 m
                             9 m
               3  A rectangle is 12 cm long and 5 cm wide.                         Draw diagrams to help you solve
                 Work out the length of a diagonal of the rectangle.               these problems.
               4  Isaac walks 8 km north and then 12 km east.
                 How far is Isaac from his starting point?
                                                                                                 16 cm        12 cm
               5  The diagram shows a triangle inside a circle with centre O.
                 The lengths of the shorter sides of the triangle are 12 cm and 16 cm.                 O
                 Work out the area of the circle.
               Summary
                You should now know that:                          You should be able to:

                +   An inscribed shape fits inside a circle with all its   +   Use a straight edge and compasses to construct
                   vertices (corners) on the circumference of the     the perpendicular from a point on a line and the
                   circle.                                            perpendicular from a point to the line.
                +   Pythagoras’ theorem can only be used to solve   +   Use a straight edge and compasses to inscribe
                   problems in right-angled triangles. The theorem    squares, equilateral triangles and regular
                   states that: a  = b  + c , where a is the hypotenuse   hexagons and octagons by constructing equal
                              2
                                  2
                                     2
                   and b and c are the two shorter sides.             divisions of a circle.
                                                                   +   Know and use Pythagoras’ theorem to solve
                                                                      two-dimensional problems involving right-angled
                                                                      triangles.
       82      8 Constructions and Pythagoras’ theorem
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