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8.3 Using Pythagoras’ theorem



               8.3 Using Pythagoras’ theorem


               $e longest side of a right-angled triangle is called the hypotenuse.                 Hypotenuse
               $e hypotenuse is the side that is opposite the right angle.
               Now look at this triangle. $e length of the hypotenuse is labelled a and
               the lengths of the other two sides are b and c.
                                                                                                         a
               Pythagoras’ theorem states that in any right-angled triangle, the square of    b
               the hypotenuse is equal to the sum of the squares of the other two sides.
                                     2
               For this triangle: a  = b  + c 2                                                         c
                                 2
               You can use this formula to solve problems involving right-angled triangles.



               Worked example 8.3
                a  A right-angled triangle has a base length of 1.2 m and a perpendicular height of 0.9 m.
                   What is the length of the hypotenuse of the triangle?
                b  A ladder is 5 m long. Dave rests the ladder against a vertical brick wall. The foot of the ladder is 1.5 m
                    horizontally from the base of the wall. How far up the wall does the ladder reach?

                a                         Start by drawing a triangle to represent the problem. Write the dimensions
                   0.9 m                  that you know on the triangle.
                            1.2 m

                               a =        Label the sides of the triangle a, b and c. Label the hypotenuse a and the
                   b = 0.9                other two sides b and c. It doesn’t matter which is which.

                             c = 1.2
                   a  = b  + c            Write down the formula, then substitute in the numbers that you know.
                             2
                    2
                         2
                   a  = 0.9  + 1.2        Solve the equation to work out the value of a. Take it one step at a time.
                    2
                                2
                           2
                   a  = 0.81 + 1.44
                    2
                   a  = 2.25
                    2
                    a =  225.             Use your calculator to work out the square root.
                    a = 1.5 m             Remember to write the correct units (metres) with your answer.
                b                         Start by drawing a triangle to represent the problem. Write the dimensions
                   a = 5 m                that you know on the triangle.
                             b =
                                          Label the sides of the triangle a, b and c.
                      c = 1.5 m
                    a  = b  + c           Write down the formula, then substitute in the numbers that you know.
                     2
                             2
                         2
                    5  = b  + 1.5         Solve the equation to work out the value of b. Take it one step at a time.
                         2
                               2
                     2
                   25 = b  + 2.25
                          2
                    b  = 25 − 2.25
                     2
                    b  = 22.75
                     2
                     b =  22 75.           Use your calculator to work out the square root.
                     b = 4.77 m (2 d.p.)   If your answer isn’t exact, round it to two decimal places. Put the units in
                                           your answer.
                                                                               8 Constructions and Pythagoras’ theorem  81
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