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EXAMPLE 3:                                                                                              x   2    y       2        2gx              2 fy         c             0



        Find the centre and the length of the
                                                                                                                                         Center , C = ( - g , - f )

        radius of the circle x                        y       6x     12y                                                                                              2         2
                                                 2
                                                          2
                                                                                    2 0
        Solution :                                                                                                                        Radius ,  r                 g         f        c



        By comparing the equation to the general form


                                                                                  
                                      x         y        2gx          2 fy c              0
                                                    2
                                         2

        We find                 2g           6 and 2 f                12


                                    g         3 and f                6




                                                                                                  
                                                               g 
                                                                
                                                                      , f 
                                                                                            
                                                                                3, 6
        so we obtain the centre at                                   and
                                        r         g         f       c
                                                                 2
                                                       2


                                                            2
                                                                      2
                                        r         (     ) 3     6        (     ) 2


                                        r        47
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