Page 9 - PowerPoint Presentation

The centre of the circle, (h,k) is

3 1 8 14   
( , ) k    2 , 2  
h

( , )h k  2,11 

The circle has equation

2
2

x h     r 2
  y k

Substituting h = 2, k = 11 and r  10 into the equation gives

2
2
 x  2   y  11     2
10

x  y  4x  22y  115 0
2
2