Page 41 - E-MODUL FLUIDA STATIS (Riski Handani Gultom_4173121044)

Riski Handani Gultom
Prof. Dr. Makmur Sirait, M.Si

PEMBAHASAN LATIHAN SOAL

o
1. Diketahui : θ = 0
2
L = 10 cm = 0,1 m g = 10 m/s
2
g = 9,8 m/s Ditanyakan, h= …?
-3
massa kawat = mk = 0,3.10 kg Jawab
-3
massa beban = mb = 0,2.10 kg h = 2γ cos ρ g. R
-3
-5
Ditanyakan, γ ? = 2. 72,8.10 . 1. 1000. 10. 10
-4
F = W kawat + W beban = 145,6.10
-2
= mk. g + mb . g = 1,456 . 10 m
-3
-3
= 0,3.10 .9,8 + 0,2.10 .9.8 4. Diketahui
-3
= 0,5.10 .9,8 D = 1 cm = 0,01 cm
-3
-2
= 4, 90 10 N r = 0,5.10 m
3
3
ρf = 0,8 gr/cm = 800 kg/m

3 3
ρk = 2,6 gr/cm = 2600 kg/m
= η = 0,03 Pas

2
-2
= 2,45 . 10 N/m g = 10 m/s
2. Diketahui Ditanya V = ..?

L = 10 cm = 0,1 m V = –

-3
F = 4 . 10 N

= –
Ditanyakan γ = …?

γ = 2 = . 1800
−3
−1
= 4.10 2.10
=
= 2.10 N/m
-2

=
3. Diketahui
-5
R = 10 m = 3,33 m/s
-3
γ = 72,8.10 N/m

Modul Fluida Statis | Kelas XI SMA 40