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POYNTING's THEOREM                                                      133

            numerical solution. Poynting’s theorem lets remove the wall between Maxwell’s equations and
            much  more transparent circuit  theory. It  allows updating  the lumped elements equivalent
            circuits and including in analysis mutual coupling effects between elements. In general, the
            output of such hybrid analysis is the equivalent circuit model so it can be easily integrated with
            other active and passive circuit models for a conventional circuit simulation.

            We know that the electric and magnetic fields can exist not only in capacitors or inductances
            but within any region of free space or space filled with matter. If so, we show in the next chapter
            how to build an equivalent circuit of material free or filled up space using lumped elements.


            3.1.16  Poynting’s Theorem in Space-Frequency Domain

            In general, the direct measurement of instantaneous power considered above is very challenging
            and  difficult procedure requiring an  ultra-fast EM  field  sensor in assembly  with  highly
            sophisticated and expensive instruments. One way around is to measure, as an alternative, the
            “time-average” in-phase and quadrature magnitude of power defined in Chapter 1 (see (1.80)).

            The differential form of energy conservation law in the space-frequency domain. Following
            (1.83) we can express the average power through the dot (∘) or cross (x) product of two phasor-
            vectors (, )exp () and (, )exp () as


                       1                                    1
                                          ∗
                                                                       ∗
                        (, ) exp() ∘  (, ) exp(−) = (, ) ∘  (, )
                       2                                    2
                       1                                    1
                                                                       ∗
                                          ∗
                        (, ) exp()  x  (, ) exp(−) = (, ) x  (, )
                       2                                    2
            where (, ) = |(, )|   ()   ,(, ) = |(, )|    () . The  values   ()  and
                                                                               
             () is the phase of (, ) and (, ), respectively. Both products belong to the space-
             
            frequency domain and, evidently, are the time-independent values. Then (3.2) can be rewritten
            as
                                                              ∗
                                                        ∗
                                                ∗
                                   /2   ∘   x  = − +  + (  ∗
                                                                     )
                                         �                           �               (3.44)
                                     ∗
                                    /2 ∘       − x  = 
            Here the factor  replaces the time derivatives (see Table 1.9) and the complex conjugate
            operator applied to the right-hand side of the first equation  in (3.44) revises  the factor  
            to – . Taking scalar product or dotting the top equation in (3.44) with  and bottom one
            with  , as shown in (3.44), we get summing all the products
                 ∗
               1        ∗  1  ∗            1      ∗    ∗      1      ∗  1   ∗
                 ∘  x  −  ∘  x  = − ( ∘  −  ∘ ) +  ∘  + (  ) ∘   (3.45)
               2           2               2                  2         2  
                                                                    ∗   ∗
            Applying the vector identity  (A.35)  from  Appendix,    ∘  x  −  ∘  x    = − ∘
            ( x  ), we can transform (3.45) and obtain after regrouping the terms
                 ∗
                            ) ∘  =  ∘ ( x  ) − ( ∘  −  ∘ ) +  ∘ 
                       1           1             1                    1
                         − (  ∗  ∗        ∗   ∗             ∗      (3.46)
                       2    2            2                    2
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