Page 151 - Mechatronics with Experiments
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MECHANISMS FOR MOTION TRANSMISSION  137
                             linear distance traveled by each gear at the contact point is same,

                                                              s = s                             (3.18)
                                                               1   2
                                                          Δ   ⋅ r =Δ   ⋅ r                      (3.19)
                                                            1  1     2  2
                                                                   Δ   1
                                                               N =                              (3.20)
                                                                   Δ   2
                                                                   r 2
                                                               N =                              (3.21)
                                                                   r 1
                             Since the pitch of each gear must be same, the number of teeth on each gear is proportional
                             to their radius,
                                                                ̇ 1  N 2  r 2
                                                         N =    =    =                          (3.22)
                                                                ̇ 2  N 1  r 1
                             where N and N are the number of gear teeth on each gear. It can be shown that for an
                                    1
                                           2
                             ideal gear box (100% power transmission efficiency),
                                                             P out  = P in                      (3.23)
                                                         T out  ⋅    ̇  out  = T ⋅    ̇ in      (3.24)
                                                                    in
                             Hence,
                                                            N 2      ̇ in  T out
                                                        N =    =     =                          (3.25)
                                                            N 1     ̇ out  T in
                             The reflection of inertia and torque from the output shaft to the input shaft can be determined
                             by using the energy and work relationships. Let the rotary inertia of the load on the output
                             shaft be J and the load torque be T . Let us express the kinetic energy of the load
                                     l                   l
                                                             1
                                                        KE =   ⋅ J ⋅    ̇ 2 out                 (3.26)
                                                                 l
                                                             2
                                                             1          2
                                                                    ̇
                                                           =   ⋅ J ⋅ (   ∕N)                    (3.27)
                                                                 l
                                                                    in
                                                             2
                                                             1     1      2
                                                                        ̇
                                                           =   ⋅ J ⋅  ⋅ (   )                   (3.28)
                                                                        in
                                                                 l
                                                             2     N 2
                                                             1           2
                                                                      ̇
                                                           =   ⋅ J in,eff  ⋅ (   )              (3.29)
                                                                       in
                                                             2
                             where the reflected inertia (inertia of the load seen by the input shaft) is
                                                                    J l
                                                             J in,eff  =                        (3.30)
                                                                   N 2
                             Similarly, let us determine the effective load torque seen by the input shaft. The work done
                             by a load torque T over an output shaft displacement Δ   out  is
                                            l
                                                          W = T ⋅ Δ   out                       (3.31)
                                                                l
                                                                  Δ  
                                                             = T ⋅  in                          (3.32)
                                                                l
                                                                   N
                                                             = T    ⋅ Δ                         (3.33)
                                                                in,eff  in
                             The effective reflective torque on the input shaft as a result of the load torque on the output
                             shaft is
                                                                    T l
                                                             T in,eff  =                        (3.34)
                                                                    N
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