Page 16 - MATERI MATRIKS E- BOOK
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M33
                      3   2   0      3   2
                      |1  1   2|  = | 1  1 | = (3.1) – (2.1) = 3 – 2 = 1
                      3   2   1




                               1   2      1   2       1 1
                             + |     |  – |    |   + |     |
                               2   1      3   1       3 2
                            |  2   0       3  0       3   2  |        M11  | 1  2 | = (1.1) – (2.2) = 1- 4 = -3
                         = – |      |   + |     |  – |     |                2   1
                            |  2   1       3  1       3   2 |
                               2   0      3   0       3   2
                             + |     |  – |    |   + |     |
                               1   2      1   2       1   1
                                                                           1   2
                                                                      M12 |     | = (1.1) – (2.3) = 1 - 6 = -5
                                                                           3   1
                            +   −   +
                         = |−   +   −|
                            +   −   +                                       1   1
                                                                       M13 |     | = (1.2) – (3.1) = 2- 3 = -1
                                                                            3   2

                            +(−3)    −(−5)     +(−1)
                         = | −2        +3       −0 |
                              +4       −6       +1


                            −3     5    −1
                         = |−2     3    0 |
                             4    −6    1                                 2   0
                                                                     M21 |     | = (2.1) – (0.2) = 2 – 0 = 2
                  3.  Adjoin (mengubah baris menjadi kolom)               2   1
                          −3    5    −1
                         |−2    3     0 |                                 3 0
                           4    −6    1                               M22| 3 1 | = (3.1) – (0.3) = 3 – 0 = 3


                            −3    −2    4
                         = | 5     3    −6|                           M23 | 3  2 | = (3.2) – (2.3) = 6 – 6 = 0
                            −1     0    1                                 3   2










                                                                          2  0
                                                                     M31 |     | = (2.2) – (0.1) = 4 – 0 = 4
                                                                          1  2


                                                                          3  0
                                                                     M32 |     | = (3.2) – (0.1) = 6 – 0 = 6
                                                                          1  2


                                                                          3  2
                                                                     M33 |     | = (3.1) – (2.1) = 3 – 2 = 1
                                                              15          1  1
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