Page 71 - Mathématiques RAC1 volume 1 2020
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            Exercice 2.3   Réduis les sommes (ou différences) de monômes semblables :

             1)  (5xy – x y + 2xy) + (5xy – xy + 2x y) =
                                                    2
                                                           2
                      2
                           2
             2)  (a b + 3ab) + (– 5a b + 2ab) + (– 4a b − ab) =
                   2
                                                             2
                                        2
             3)  (3x − 4y + z) + (2x – y + 2z) =



             4)  (4a − 7a + 2) – (– 2a + 3a – 2) =
                                          2
                     2

                       2
             5)  – (4x – 2x + 4) + (– 4x – 7x + 1) =
                                            2

             6)  (4ab – 5a b) – (3ab + 2a b) =
                      2
                                                2
                                         2
                             2
             7)  – (2a – 3b ) – (7a + b ) + (3a – b ) =
                                                     3
                                            2
                       3
                                      3
                              2
                                                          2
             8)  (2x – 3y + z) + (5x + y – 3z) =
             9)  (5a  + 2a – 1) – (– 3a  + 7a – 2) =
                     2
                                           2

             10)  – (2x – x + y) + (4x – x – 2y) =
                                           2
                         2

             11)  (4a b – 2ab + 3ab) – (4ab – 2ab + 3ab) =
                                 2
                       2
                                                   2
                                                            2
             12)  – (x – 4y ) + (2x – 3y ) – (2y + 4x ) =
                                              2
                              2
                        2
                                                             2
                                                      2
                                       2
                                             2
                       2
             13)  (3x – 7x + 2) + (– 4x + 5x – 3) =
             14)  – (7a – 2a b + b ) + (– 4a  + a b – 7b ) =
                                                   3
                                        3
                                                         2
                                2
                                                                  3
                         3
             15)  3x y + 7xy – (–3x y + 2xy ) – 7x y + 10xy =
                      2
                                                           2
                                                                       2
                                 2
                                                   2
                                         2
             16)  – y  – [5y  – (2y  + 3y )] =
                                      2
                               2
                       2
                                              2
             17)  2y – [4y – (2y – 5y)] =


            ES Nyon-Marens BAMV                       ed 2020                                 maths Rac2
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