Page 71 - Mathématiques RAC1 volume 1 2020
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Exercice 2.3 Réduis les sommes (ou différences) de monômes semblables :
1) (5xy – x y + 2xy) + (5xy – xy + 2x y) =
2
2
2
2
2) (a b + 3ab) + (– 5a b + 2ab) + (– 4a b − ab) =
2
2
2
3) (3x − 4y + z) + (2x – y + 2z) =
4) (4a − 7a + 2) – (– 2a + 3a – 2) =
2
2
2
5) – (4x – 2x + 4) + (– 4x – 7x + 1) =
2
6) (4ab – 5a b) – (3ab + 2a b) =
2
2
2
2
7) – (2a – 3b ) – (7a + b ) + (3a – b ) =
3
2
3
3
2
2
8) (2x – 3y + z) + (5x + y – 3z) =
9) (5a + 2a – 1) – (– 3a + 7a – 2) =
2
2
10) – (2x – x + y) + (4x – x – 2y) =
2
2
11) (4a b – 2ab + 3ab) – (4ab – 2ab + 3ab) =
2
2
2
2
12) – (x – 4y ) + (2x – 3y ) – (2y + 4x ) =
2
2
2
2
2
2
2
2
13) (3x – 7x + 2) + (– 4x + 5x – 3) =
14) – (7a – 2a b + b ) + (– 4a + a b – 7b ) =
3
3
2
2
3
3
15) 3x y + 7xy – (–3x y + 2xy ) – 7x y + 10xy =
2
2
2
2
2
2
16) – y – [5y – (2y + 3y )] =
2
2
2
2
17) 2y – [4y – (2y – 5y)] =
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