Page 77 - Lydia Chen - The Complete Book of Chinese Knotting
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05 Constellation Knot (65-80)  3/23/07  4:03 PM  Page 74











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                                                                                                                                                                                                                                                    Step 5. 5 –  1 +  2 –  3 +  4 +  1 –  2 +  3
                                                                                                                                                                                                                                                    Step 6. 6 –  2 +  3 –  4 +  5 –  1 +   2 –  3 +  4
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                                                                                                                                                                                                     1
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                                                                                                                                                                                                                  5 Completed knot























                                                                                                                                                                                                 Formula for Type 1 Compound constellation knot with multiple outer loops:
                                                                                                                                                                                                 a. (x) – (x–4) + (x–3) – (x–2) + (x–1)
                                                                                                                                                                                                 b. (n–3) – (n–3–4) + (n–3–3) – (n–3–2) + (n–3–1) +  1
                                                                                                                                                                                                  (n–2) – (n–2–4) + (n–2–3) – (n–2–2) + (n–2–1) –  1 +  2
                                                                                                                                                                                                  (n–1) – (n–1–4) + (n–1–3) – (n–1–2) + (n–1–1) +  1 –  2 +  3
                                                                                                                                                                                                  (n) – (n–4) + (n–3) – (n–2) + (n–1) –  1 +  2 –  3 +  4
                                                                                                                                                                                                 Formula application:
                                                                                                                                                                                                 1.“x”denotes the number of each ear loop.
                                                                                                                                                                                                  “n”denotes the total number of ear loops;“n”is bigger than 4.
                                                                                                                                                                                                 2.When the value of “x”is not enough for deduction, then that item does not exist.
                                                                                                                                                                                                  Example x = 3 and insert this into the equation to give  3 +  1 +  2
                                                                                                                                                                                                        x = 5 and insert this into the equation to give  5 –  1 +  2 –  3 +  4
                                                                                                                                                                                                 3. Use formula “a”for all ear loops except the number 4 by counting backwards.
                                                                                                                                                                                                  Use formula “b”for this particular ear loop.
                                                                                                                                                                                                                                                         Type 1 Compound constellation knot.




                                                                                                                                                                                              74  CONSTELLATION KNOT
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