Page 83 - Lydia Chen - The Complete Book of Chinese Knotting

05 Constellation Knot (65-80) 3/23/07 4:03 PM Page 80

3
5

6

4

4

1

3

2

Step 5. 5 – 1 – 2 + 3 + 4 – 1 + 2 + 3
Step 6. 6 – 2 – 3 + 4 + 5 – 1 – 2 + 3 + 4

5 Completed knot

Formula for Type 4 Compound constellation knot with multiple outer loops:
a. (x) – (x–4) – (x–3) + (x–2) + (x – 1)
b. (n–3) – (n–3 –4) – (n–3–3) + (n– 3–2) + (n–3–1) + 1
(n–2) – (n–2–4) – (n–2–3) + (n–2–2) + (n–2–1) + 1 + 2
(n–1) – (n–1–4) – (n–1–3) + (n–1–2) + (n–1–1) – 1 + 2 + 3
(n) – (n–4) – (n–3) + (n–2) + (n–1) – 1 – 2 + 3 + 4

Formula application:
1.“x”denotes the number of each ear loop.
“n”denotes the total number of ear loops;“n”is bigger than 4.
2.When the value of “x”is not enough for deduction, then that item does not exist.
Example x = 3 and insert this into the equation to give 3 + 1 + 2
x = 5 and insert this into the equation to give 5 – 1 – 2 + 3 + 4
3. Use formula “a”for all ear loops except the number 4 by counting backwards.
Use formula “b”for this particular ear loop.
Type 4 Compound constellation knot.

80 CONSTELLATION KNOT