Page 44 - E-MODUL HUKUM NEWTON GRAVITASI KURIKULUM 2013_REVISI

m m b
B
F = G
M
r B−b 2
22
30
F = 6,67 × 10 ;11 Nm 2 kg 2 7,35×10 kg 1,99×10 kg
M
2
11
m
1,5×10
52
2
F = 6,67 × 10 ;11 Nm 2 kg 2 14,626×10 22 kg
M
2
2,25×10 m
F = 6,67 × 10 ;11 Nm 2 kg 2 × 6,5 × 10 22 kg 2 m 2
M
F = 4,3 × 10 N
20
M
Karena kedua gaya membentuk sudut siku-siku, maka:

F = F b 2 + F M 2
B

F = 1,99 × 10 + 4,3 × 10
20 2
20 2
B
40
F = 3,9601 × 10 40 + 18,49 × 10
B
F = 22,45 × 10
40
B
20
F = 4,73 × 10 N
B

41 | H U K U M N E W T O N T E N T A N G G R A V I T A S I