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Modul Matematika SMK X/1
Fungsi Komposisi =
Kunci Jawaban
1. (f o g)(x) = f(g(x))
= ( (
=
=
2. (g o f)(x) = g(f(x))
= (
=
=
=
3. Misal 2x+5 = p maka x =
(f o g)(x) =
f(g(x)) =
f(2x + 5) =
f(p) = 4( ) ( )
= ( ) (
=
=
Jadi, f(x) =
4. (f o g)(x) =
f(g(x)) =
2(g(x)) +3 =
2(g(x)) =
2(g(x)) =
g(x) =
5. Dari tabel diperoleh
g(1)=0, f(0)=1, g(2) = 1, f(1)=3, dan g(3) = 2
maka :
(f o g)(1)+( g o f o g )(2) = g(g(1))+(g(f(g(2)))
= f(0) + g(f(1))
= 1+g(2)= 1+2 = 3
Modul Matematika SMK X/1 “ Fungsi Komposisi” 11
