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Modul Matematika SMK X/1
Fungsi Komposisi =
(f o g) (x) = f(g(x)) = 6x – 3, sehingga x pada f(x) diganti g(x):
2g(x) + 5 = 6x – 3
2g(x) = 6x – 3 – 5 = 6x – 8
g(x) = (6x – 8) / 2 = 3x – 4
5. Diberikan dua fungsi f(x) = dan g(x)= x + 5 tentukanlah
a. ( f o g )(x)
b. ( g o f )(x)
Jawab:
a. ( f o g )(x) = f (x) o g (x)
= ( o (x + 5)
= 2( (
= 2 (
=
=
b. ( g o f )(x) = g (x) o f (x)
= (x + 5) o (
= (
=
Modul Matematika SMK X/1 “ Fungsi Komposisi” 7
