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 UAE_Math_Grade_12_Vol_1_SE_718383_ch3
                                                               13:38
                                                    July 4, 2016
               y          QC: OSO/OVY  An estimate of the number of cameras sold at x = 7 would then be
                                     L(7) ≈ 84 − 6 = 78 thousand. We show a graphical interpretation of this in Figure
           Number of cameras sold  60  Newton’s Method
                                     4.6, where the straight line is the linear approximation (in this case, the secant line
             80
                                     joining the first two data points).
             40
             20
                                     troduced the method of bisections as one procedure for finding zeros of a continuous
              0                  x   We now return to the question of finding zeros of a function. Previously,  we in-
               0   57   10   15      function. Here, we explore a method that is usually much more efficient than bisec-
                  Price of cameras   tions. Again, values of x such that f(x) = 0 are called roots of the equation f(x) = 0 or
                                     zeros of the function f. While it’s easy to find the zeros of
                 FIGURE 4.6
                                                                         2
              Linear interpolation                               f(x) = ax + bx + c,
                                     how would you find zeros of
                                                                   f(x) = tan x − x?
                                     Since this function is not algebraic, there are no formulas available for finding the zeros.
                                     Even so, we can clearly see zeros in Figure 4.7. (In fact, there are infinitely many of
                                     them.) The question is, how are we to find them?


                                                       y                                      y
                                                      5


                                                                                 y = f(x)
                                                                     x
                                                -3           3



                                                                                                      x
                                                    -5                        x 0  x 1  x 2

                                                   FIGURE 4.7                       FIGURE 4.8
                                                   y = tan x − x                   Newton’s method


                  HISTORICAL             In general, to find approximate solutions to f(x) = 0, we first make an initial guess,
                  NOTES              denoted x , of the location of a solution. Following the tangent line to y = f(x) at x =
                                              0
                                     x to where it intersects the x-axis (see Figure 4.8) appears to provide an improved
                                      0
          Sir I. Newton (1642–1727) An  approximation to the zero. The equation of the tangent line to y = f(x) at x = x is
          English mathematician and  given by the linear approximation at x [see equation (1.1)],         0
          scientist known as the                                     0
                                                                         ′
          co-inventor of calculus. In a                        y = f(x ) + f (x )(x − x ).               (1.7)
          2-year period from 1665 to 1667,                           0     0      0
          Newton made major discoveries  We denote the x-intercept of the tangent line by x [found by setting y = 0 in (1.7)]. We
                                                                              1
          in several areas of calculus, as  then have
          well as optics and the law of                                  ′
          gravitation. Newton’s                                0 = f(x ) + f (x )(x − x )
                                                                                  0
                                                                     0
                                                                           0
                                                                              1
          mathematical results were not  and, solving this for x ,weget
          published in a timely fashion.               1
          Instead, techniques such as                                      f(x )
                                                                              0
                                                                        0
                                                                   1
          Newton’s method were quietly                            x = x −  f (x )  .
                                                                            ′
          introduced as useful tools in his                                   0
          scientific papers. Newton’s  Repeating this process, using x as our new guess, should produce a further improved
                                                               1
          Mathematical Principles of  approximation,
          Natural Philosophy is widely                                     f(x )                                    Copyright © McGraw-Hill Education
          regarded as one of the greatest                          x = x −    1
                                                                            ′
          achievements of the human                                 2   1  f (x )
                                                                              1
          mind.
        232 | Lesson 4-1 | Linear Approximations and Newton’s Method
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