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                               GO01962-Smith-v1.cls
 UAE_Math_Grade_12_Vol_1_SE_718383_ch3
                                                 July 4, 2016
                                     We now consider the limit  13:38
                                                 lim ln y = lim  1  ln x  (∞ ⋅ 0)
                                                            +
                                                x→1 +     x→1 x − 1
                                                               ln x  ( )
                                                                      0
                                                        = lim
                                                          x→1 x − 1   0
                                                            +
                                                               d  (ln x)
                                                               dx            x −1
                                                        = lim         = lim     = 1.  By l’Ĥopital’s Rule.
                                                          x→1 +  d  (x − 1)  x→1 +  1
           y                                                  dx
                                     Be careful; we have found that lim ln y = 1, but this is not the original limit. We
         1.0                                                   x→1 +
                                     want
         0.9                                                   lim y = lim e ln y  = e ,
                                                                                 1
                                                               x→1 +  x→1 +
         0.8                         which is consistent with Figure 4.21.

         0.7                             The computation of limits often requires several applications of l’Ĥopital’s Rule.
                                     Just be careful (in particular, verify the hypotheses at every step) and do not lose sight
                                  x  of the original problem.
              0.2  0.4  0.6  0.8  1.0
                FIGURE 4.22
                  y = (sin x) x      EXAMPLE 2.9      The Indeterminate Form 0  0
                                                     x
                                     Evaluate lim (sin x) .
                                             x→0 +
                                                                                0
                                     Solution This limit has the indeterminate form (0 ). In Figure 4.22, it appears that
                                                                               x
                                     the limit is somewhere around 1. We let y = (sin x) , so that
                                                                        x
                                                            ln y = ln (sin x) = x ln (sin x).
                                     Now consider the limit
                                                   lim ln y = lim ln (sin x) = lim [x ln (sin x)] (0 ⋅ ∞)
               TODAY IN                           x→0 +     x→0 +      x  x→0 +
               MATHEMATICS                                      ln (sin x)  ( ∞  )
                                                          = lim  ( )
          Vaughan Jones (1952–  )                           x→0 +  1       ∞
          A New Zealand mathematician                              x
          whose work has connected                               d
          apparently disjoint areas of                           dx [ln (sin x)]
          mathematics. He was awarded                     = lim +  d         By l’Ĥopital’s Rule.
                                                                      −1
          the Fields Medal in 1990 for                      x→0      (x )
          mathematics that was described                          dx
          by peers as ‘astonishing’. One of                       1  cos x  (  )
          his major accomplishments is a                  = lim  sin x       ∞  .
          discovery in knot theory that has                 x→0 +  −x −2     ∞
          given biologists insight into the  As we have seen earlier, we should rewrite the expression before proceeding. Here,
                                                                 2
          replication of DNA. A strong  we multiply top and bottom by x sin x to get
          supporter of science and                                   1
          mathematics education in New                             sin x  cos x  ( x sin x  )
                                                                               2
          Zealand, Jones’ “style of working           lim ln y = lim +  −x −2  x sin x
                                                                               2
                                                        +
          is informal, and one which                 x→0       x→0
                                                                     2
                                                                               0
          encourages the free and open                       = lim  −x cos x  ( )
          interchange of ideas . . . . His                     x→0 +  sin x    0
          openness and generosity in                                d  (−x cos x)
                                                                        2
          this regard have been in the                             dx
          best tradition and spirit of                       = lim +  d         By l’Ĥopital’s Rule.
                                                               x→0
          mathematics.” His ideas have                               dx (sin x)
          “served as a rich source of ideas                                   2                                     Copyright © McGraw-Hill Education
          for the work of others.”                           = lim  −2x cos x + x sin x  =  0  = 0.
                                                               x→0 +     cos x        1

        246 | Lesson 4-2 | Indeterminate Forms and L’Hôpital’s Rule
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